Doubt & Answer Explanation

Answer Explanation

Sol. Here, we have a room surrounded by a varandha



We have given,
Area of room =5 x 4
=20m²
Area of square =22m²
Therefore Area of entire ABCD=(20+22)
(5+2x)(4+2x) =42
20+10x+8x+9x² =42
4x² +18x+20=42
2x² +9x+10=21
2x²+9x-11=0
2x² +112-2x-11=0
x(2x+11)-1(2² +1)=0
(2x+11)(x-1) =0
x=-11/2  , x=11

Hence, the width of the varandha is1.