Answer Explanation
4M can do a work in 12 days
Let a denotes the work done by one man in one day
4a x 12 = 1 ( Let 1 denotes the total work)
a = 1/48
Similarly 6 women can do the same work in 12 days
Let b denotes the work done by one woman in one day
6b x 12 = 1
b = 1/72
Now 4men and 12 women are working together
Let the number of days required = n
n ( 4 x a + 12 x b) = 1
n ( 4 x 1/48 + 12 x 1/72) = 1
n ( 1/12 + 1/6) = 1
n /4 = 1
n = 4 days
